Python Language
Listes liées
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Introduction
Une liste chaînée est une collection de nœuds, chacun composé d'une référence et d'une valeur. Les nœuds sont assemblés en une séquence en utilisant leurs références. Les listes liées peuvent être utilisées pour implémenter des structures de données plus complexes telles que les listes, les piles, les files d'attente et les tableaux associatifs.
Exemple de liste liée unique
Cet exemple implémente une liste liée avec plusieurs des mêmes méthodes que celle de l'objet de liste intégré.
class Node:
def __init__(self, val):
self.data = val
self.next = None
def getData(self):
return self.data
def getNext(self):
return self.next
def setData(self, val):
self.data = val
def setNext(self, val):
self.next = val
class LinkedList:
def __init__(self):
self.head = None
def isEmpty(self):
"""Check if the list is empty"""
return self.head is None
def add(self, item):
"""Add the item to the list"""
new_node = Node(item)
new_node.setNext(self.head)
self.head = new_node
def size(self):
"""Return the length/size of the list"""
count = 0
current = self.head
while current is not None:
count += 1
current = current.getNext()
return count
def search(self, item):
"""Search for item in list. If found, return True. If not found, return False"""
current = self.head
found = False
while current is not None and not found:
if current.getData() is item:
found = True
else:
current = current.getNext()
return found
def remove(self, item):
"""Remove item from list. If item is not found in list, raise ValueError"""
current = self.head
previous = None
found = False
while current is not None and not found:
if current.getData() is item:
found = True
else:
previous = current
current = current.getNext()
if found:
if previous is None:
self.head = current.getNext()
else:
previous.setNext(current.getNext())
else:
raise ValueError
print 'Value not found.'
def insert(self, position, item):
"""
Insert item at position specified. If position specified is
out of bounds, raise IndexError
"""
if position > self.size() - 1:
raise IndexError
print "Index out of bounds."
current = self.head
previous = None
pos = 0
if position is 0:
self.add(item)
else:
new_node = Node(item)
while pos < position:
pos += 1
previous = current
current = current.getNext()
previous.setNext(new_node)
new_node.setNext(current)
def index(self, item):
"""
Return the index where item is found.
If item is not found, return None.
"""
current = self.head
pos = 0
found = False
while current is not None and not found:
if current.getData() is item:
found = True
else:
current = current.getNext()
pos += 1
if found:
pass
else:
pos = None
return pos
def pop(self, position = None):
"""
If no argument is provided, return and remove the item at the head.
If position is provided, return and remove the item at that position.
If index is out of bounds, raise IndexError
"""
if position > self.size():
print 'Index out of bounds'
raise IndexError
current = self.head
if position is None:
ret = current.getData()
self.head = current.getNext()
else:
pos = 0
previous = None
while pos < position:
previous = current
current = current.getNext()
pos += 1
ret = current.getData()
previous.setNext(current.getNext())
print ret
return ret
def append(self, item):
"""Append item to the end of the list"""
current = self.head
previous = None
pos = 0
length = self.size()
while pos < length:
previous = current
current = current.getNext()
pos += 1
new_node = Node(item)
if previous is None:
new_node.setNext(current)
self.head = new_node
else:
previous.setNext(new_node)
def printList(self):
"""Print the list"""
current = self.head
while current is not None:
print current.getData()
current = current.getNext()
L'utilisation fonctionne comme celle de la liste intégrée.
ll = LinkedList()
ll.add('l')
ll.add('H')
ll.insert(1,'e')
ll.append('l')
ll.append('o')
ll.printList()
H
e
l
l
o
Modified text is an extract of the original Stack Overflow Documentation
Sous licence CC BY-SA 3.0
Non affilié à Stack Overflow