C# Language
LINQ to XML

LINQ to XML का उपयोग करके XML पढ़ें

<?xml version="1.0" encoding="utf-8" ?>
<Employees>
 <Employee>
  <EmpId>1</EmpId>
  <Name>Sam</Name>   
  <Sex>Male</Sex>
  <Phone Type="Home">423-555-0124</Phone>
  <Phone Type="Work">424-555-0545</Phone>
  <Address>
   <Street>7A Cox Street</Street>
   <City>Acampo</City>
   <State>CA</State>
   <Zip>95220</Zip>
   <Country>USA</Country>
  </Address>
</Employee>
<Employee>
 <EmpId>2</EmpId>
 <Name>Lucy</Name>
 <Sex>Female</Sex>
 <Phone Type="Home">143-555-0763</Phone>
 <Phone Type="Work">434-555-0567</Phone>
 <Address>
  <Street>Jess Bay</Street>
  <City>Alta</City>
  <State>CA</State>
  <Zip>95701</Zip>
  <Country>USA</Country>
  </Address>
 </Employee>
</Employees>

LINQ का उपयोग करके उस XML फ़ाइल को पढ़ने के लिए

XDocument xdocument = XDocument.Load("Employees.xml");
IEnumerable<XElement> employees = xdocument.Root.Elements();
foreach (var employee in employees)
{
    Console.WriteLine(employee);
}

एकल तत्व तक पहुंचने के लिए

XElement xelement = XElement.Load("Employees.xml");
IEnumerable<XElement> employees = xelement.Root.Elements();
Console.WriteLine("List of all Employee Names :");
foreach (var employee in employees)
{
    Console.WriteLine(employee.Element("Name").Value);
}

कई तत्वों का उपयोग करने के लिए

XElement xelement = XElement.Load("Employees.xml");
IEnumerable<XElement> employees = xelement.Root.Elements();
Console.WriteLine("List of all Employee Names along with their ID:");
foreach (var employee in employees)
{
    Console.WriteLine("{0} has Employee ID {1}",
    employee.Element("Name").Value,
    employee.Element("EmpId").Value);
}

एक विशिष्ट विशेषता वाले सभी तत्वों को एक्सेस करने के लिए

XElement xelement = XElement.Load("Employees.xml");
var name = from nm in xelement.Root.Elements("Employee")
       where (string)nm.Element("Sex") == "Female"
       select nm;
Console.WriteLine("Details of Female Employees:");
foreach (XElement xEle in name)
Console.WriteLine(xEle);

विशिष्ट विशेषता वाले विशिष्ट तत्व तक पहुंचने के लिए

XElement xelement = XElement.Load("..\\..\\Employees.xml");
var homePhone = from phoneno in xelement.Root.Elements("Employee")
            where (string)phoneno.Element("Phone").Attribute("Type") == "Home"
            select phoneno;
Console.WriteLine("List HomePhone Nos.");
foreach (XElement xEle in homePhone)
{
    Console.WriteLine(xEle.Element("Phone").Value);
}