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Sintaxis

  • Función PlainAuth (identidad, nombre de usuario, contraseña, cadena de host) Aut.
  • func SendMail (cadena addr, un Auth, de cadena, a [] cadena, msg [] byte) error

Enviando correo electrónico con smtp.SendMail ()

Enviar correo electrónico es bastante simple en Go. Ayuda a comprender el RFC 822, que especifica el estilo en el que debe estar un correo electrónico, el código que aparece a continuación envía un correo electrónico compatible con RFC 822.

package main

import (
    "fmt"
    "net/smtp"
)

func main() {
    // user we are authorizing as
    from := "[email protected]"

    // use we are sending email to
    to := "[email protected]"

    // server we are authorized to send email through
    host := "mail.example.com"

    // Create the authentication for the SendMail()
    // using PlainText, but other authentication methods are encouraged
    auth := smtp.PlainAuth("", from, "password", host)

    // NOTE: Using the backtick here ` works like a heredoc, which is why all the 
    // rest of the lines are forced to the beginning of the line, otherwise the 
    // formatting is wrong for the RFC 822 style
    message := `To: "Some User" <[email protected]>
From: "Other User" <[email protected]>
Subject: Testing Email From Go!!

This is the message we are sending. That's it!
`

    if err := smtp.SendMail(host+":25", auth, from, []string{to}, []byte(message)); err != nil {
        fmt.Println("Error SendMail: ", err)
        os.Exit(1)
    }
    fmt.Println("Email Sent!")
}

Lo anterior enviará un mensaje como el siguiente:

To: "Other User" <[email protected]>
From: "Some User" <[email protected]>
Subject: Testing Email From Go!!

This is the message we are sending. That's it!
.


Modified text is an extract of the original Stack Overflow Documentation
Licenciado bajo CC BY-SA 3.0
No afiliado a Stack Overflow