Go
Enviar / recibir correos electrónicos
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Sintaxis
- Función PlainAuth (identidad, nombre de usuario, contraseña, cadena de host) Aut.
- func SendMail (cadena addr, un Auth, de cadena, a [] cadena, msg [] byte) error
Enviando correo electrónico con smtp.SendMail ()
Enviar correo electrónico es bastante simple en Go. Ayuda a comprender el RFC 822, que especifica el estilo en el que debe estar un correo electrónico, el código que aparece a continuación envía un correo electrónico compatible con RFC 822.
package main
import (
"fmt"
"net/smtp"
)
func main() {
// user we are authorizing as
from := "[email protected]"
// use we are sending email to
to := "[email protected]"
// server we are authorized to send email through
host := "mail.example.com"
// Create the authentication for the SendMail()
// using PlainText, but other authentication methods are encouraged
auth := smtp.PlainAuth("", from, "password", host)
// NOTE: Using the backtick here ` works like a heredoc, which is why all the
// rest of the lines are forced to the beginning of the line, otherwise the
// formatting is wrong for the RFC 822 style
message := `To: "Some User" <[email protected]>
From: "Other User" <[email protected]>
Subject: Testing Email From Go!!
This is the message we are sending. That's it!
`
if err := smtp.SendMail(host+":25", auth, from, []string{to}, []byte(message)); err != nil {
fmt.Println("Error SendMail: ", err)
os.Exit(1)
}
fmt.Println("Email Sent!")
}
Lo anterior enviará un mensaje como el siguiente:
To: "Other User" <[email protected]>
From: "Some User" <[email protected]>
Subject: Testing Email From Go!!
This is the message we are sending. That's it!
.
Modified text is an extract of the original Stack Overflow Documentation
Licenciado bajo CC BY-SA 3.0
No afiliado a Stack Overflow