Zoeken…


Syntaxis

  • func PlainAuth (identiteit, gebruikersnaam, wachtwoord, hoststring) Auth
  • func SendMail (addr string, een Auth, van string, naar [] string, msg [] byte) fout

E-mail verzenden met smtp.SendMail ()

E-mail verzenden is vrij eenvoudig in Go. Het helpt om de RFC 822 te begrijpen, die de stijl specificeert waarin een e-mail moet staan, de onderstaande code stuurt een e-mail die voldoet aan RFC 822.

package main

import (
    "fmt"
    "net/smtp"
)

func main() {
    // user we are authorizing as
    from := "[email protected]"

    // use we are sending email to
    to := "[email protected]"

    // server we are authorized to send email through
    host := "mail.example.com"

    // Create the authentication for the SendMail()
    // using PlainText, but other authentication methods are encouraged
    auth := smtp.PlainAuth("", from, "password", host)

    // NOTE: Using the backtick here ` works like a heredoc, which is why all the 
    // rest of the lines are forced to the beginning of the line, otherwise the 
    // formatting is wrong for the RFC 822 style
    message := `To: "Some User" <[email protected]>
From: "Other User" <[email protected]>
Subject: Testing Email From Go!!

This is the message we are sending. That's it!
`

    if err := smtp.SendMail(host+":25", auth, from, []string{to}, []byte(message)); err != nil {
        fmt.Println("Error SendMail: ", err)
        os.Exit(1)
    }
    fmt.Println("Email Sent!")
}

Bovenstaande zal een bericht sturen zoals het volgende:

To: "Other User" <[email protected]>
From: "Some User" <[email protected]>
Subject: Testing Email From Go!!

This is the message we are sending. That's it!
.


Modified text is an extract of the original Stack Overflow Documentation
Licentie onder CC BY-SA 3.0
Niet aangesloten bij Stack Overflow