Python Language
Filter

Syntaxis

• filter (functie, iterabel)
• itertools.ifilter (functie, iterabel)
• future_builtins.filter (functie, iterabel)
• itertools.ifilterfalse (functie, iterabel)
• itertools.filterfalse (functie, iterabel)

parameters

Opmerkingen

Basisgebruik van filter

Om verwijderingselementen van een reeks te filter op basis van enkele criteria:

names = ['Fred', 'Wilma', 'Barney']

def long_name(name):
    return len(name) > 5

filter(long_name, names)
# Out: ['Barney']

[name for name in names if len(name) > 5] # equivalent list comprehension
# Out: ['Barney']


from itertools import ifilter
ifilter(long_name, names)       # as generator (similar to python 3.x filter builtin)
# Out: <itertools.ifilter at 0x4197e10>
list(ifilter(long_name, names)) # equivalent to filter with lists
# Out: ['Barney']

(name for name in names if len(name) > 5) # equivalent generator expression
# Out: <generator object <genexpr> at 0x0000000003FD5D38>

# Besides the options for older python 2.x versions there is a future_builtin function:
from future_builtins import filter
filter(long_name, names)       # identical to itertools.ifilter
# Out: <itertools.ifilter at 0x3eb0ba8>

filter(long_name, names)        # returns a generator
# Out: <filter at 0x1fc6e443470>
list(filter(long_name, names))  # cast to list
# Out: ['Barney']

(name for name in names if len(name) > 5) # equivalent generator expression
# Out: <generator object <genexpr> at 0x000001C6F49BF4C0>

Filter zonder functie

Als de functieparameter None , wordt de identiteitsfunctie gebruikt:

list(filter(None, [1, 0, 2, [], '', 'a']))  # discards 0, [] and ''   
# Out: [1, 2, 'a']

[i for i in [1, 0, 2, [], '', 'a'] if i] # equivalent list comprehension

(i for i in [1, 0, 2, [], '', 'a'] if i) # equivalent generator expression

Filter als kortsluitingcontrole

filter (python 3.x) en ifilter (python 2.x) retourneren een generator zodat ze erg handig kunnen zijn bij het maken van een kortsluitingstest zoals or en and :

 # not recommended in real use but keeps the example short:
from itertools import ifilter as filter

 from future_builtins import filter

Om het eerste element te vinden dat kleiner is dan 100:

car_shop = [('Toyota', 1000), ('rectangular tire', 80), ('Porsche', 5000)]
def find_something_smaller_than(name_value_tuple):
    print('Check {0}, {1}$'.format(*name_value_tuple)
    return name_value_tuple[1] < 100
next(filter(find_something_smaller_than, car_shop))
# Print: Check Toyota, 1000$
#        Check rectangular tire, 80$
# Out: ('rectangular tire', 80)

De next geeft het volgende (in dit geval eerste) element van en is daarom de reden waarom het kortsluiting is.

Aanvullende functie: filterfalse, ifilterfalse

Er is een aanvullende functie voor filter in de itertools -module:

 # not recommended in real use but keeps the example valid for python 2.x and python 3.x
from itertools import ifilterfalse as filterfalse

from itertools import filterfalse

die werkt precies hetzelfde als de generator filter , maar houdt alleen de elementen die zijn False :

# Usage without function (None):
list(filterfalse(None, [1, 0, 2, [], '', 'a']))  # discards 1, 2, 'a' 
# Out: [0, [], '']

# Usage with function
names = ['Fred', 'Wilma', 'Barney']

def long_name(name):
    return len(name) > 5

list(filterfalse(long_name, names))
# Out: ['Fred', 'Wilma']

# Short-circuit useage with next:
car_shop = [('Toyota', 1000), ('rectangular tire', 80), ('Porsche', 5000)]
def find_something_smaller_than(name_value_tuple):
    print('Check {0}, {1}$'.format(*name_value_tuple)
    return name_value_tuple[1] < 100
next(filterfalse(find_something_smaller_than, car_shop))
# Print: Check Toyota, 1000$
# Out: ('Toyota', 1000)

# Using an equivalent generator:
car_shop = [('Toyota', 1000), ('rectangular tire', 80), ('Porsche', 5000)]
generator = (car for car in car_shop if not car[1] < 100)
next(generator)