Python Language
Pandas Transform：グループの操作をプリフォームし、結果を連結する

単純変換

まず、ダミーのデータフレームを作成します

顧客はn個の注文を有することができ、注文はm個のアイテムを有することができ、アイテムはさらに複数回注文可能であると仮定する

orders_df = pd.DataFrame()
orders_df['customer_id'] = [1,1,1,1,1,2,2,3,3,3,3,3]
orders_df['order_id'] = [1,1,1,2,2,3,3,4,5,6,6,6]
orders_df['item'] = ['apples', 'chocolate', 'chocolate', 'coffee', 'coffee', 'apples', 
                     'bananas', 'coffee', 'milkshake', 'chocolate', 'strawberry', 'strawberry']

# And this is how the dataframe looks like:
print(orders_df)
#     customer_id  order_id        item
# 0             1         1      apples
# 1             1         1   chocolate
# 2             1         1   chocolate
# 3             1         2      coffee
# 4             1         2      coffee
# 5             2         3      apples
# 6             2         3     bananas
# 7             3         4      coffee
# 8             3         5   milkshake
# 9             3         6   chocolate
# 10            3         6  strawberry
# 11            3         6  strawberry

。
。

さて、我々は顧客ごとの注文数を数えるためにパンダtransform関数を使用する

# First, we define the function that will be applied per customer_id 
count_number_of_orders = lambda x: len(x.unique())

# And now, we can tranform each group using the logic defined above
orders_df['number_of_orders_per_cient'] = (               # Put the results into a new column that is called 'number_of_orders_per_cient'
                     orders_df                            # Take the original dataframe
                    .groupby(['customer_id'])['order_id'] # Create a seperate group for each customer_id & select the order_id
                    .transform(count_number_of_orders))   # Apply the function to each group seperatly 

# Inspecting the results ... 
print(orders_df)
#     customer_id  order_id        item  number_of_orders_per_cient
# 0             1         1      apples                           2
# 1             1         1   chocolate                           2
# 2             1         1   chocolate                           2
# 3             1         2      coffee                           2
# 4             1         2      coffee                           2
# 5             2         3      apples                           1
# 6             2         3     bananas                           1
# 7             3         4      coffee                           3
# 8             3         5   milkshake                           3
# 9             3         6   chocolate                           3
# 10            3         6  strawberry                           3
# 11            3         6  strawberry                           3

グループごとに複数の結果

グループごとにサブ計算を返すtransform関数を使用transform

前の例では、クライアントごとに1つの結果が得られました。ただし、グループに異なる値を返す関数を適用することもできます。

# Create a dummy dataframe
orders_df = pd.DataFrame()
orders_df['customer_id'] = [1,1,1,1,1,2,2,3,3,3,3,3]
orders_df['order_id'] = [1,1,1,2,2,3,3,4,5,6,6,6]
orders_df['item'] = ['apples', 'chocolate', 'chocolate', 'coffee', 'coffee', 'apples', 
                     'bananas', 'coffee', 'milkshake', 'chocolate', 'strawberry', 'strawberry']


# Let's try to see if the items were ordered more than once in each orders

# First, we define a fuction that will be applied per group
def multiple_items_per_order(_items):
    # Apply .duplicated, which will return True is the item occurs more than once.
    multiple_item_bool = _items.duplicated(keep=False) 
    return(multiple_item_bool)

# Then, we transform each group according to the defined function
orders_df['item_duplicated_per_order'] = (                    # Put the results into a new column 
                        orders_df                             # Take the orders dataframe
                        .groupby(['order_id'])['item']        # Create a seperate group for each order_id & select the item
                        .transform(multiple_items_per_order)) # Apply the defined function to each group separately

# Inspecting the results ... 
print(orders_df)
#     customer_id  order_id        item  item_duplicated_per_order
# 0             1         1      apples                      False
# 1             1         1   chocolate                       True
# 2             1         1   chocolate                       True
# 3             1         2      coffee                       True
# 4             1         2      coffee                       True
# 5             2         3      apples                      False
# 6             2         3     bananas                      False
# 7             3         4      coffee                      False
# 8             3         5   milkshake                      False
# 9             3         6   chocolate                      False
# 10            3         6  strawberry                       True
# 11            3         6  strawberry                       True