Swift Language
Functioneel programmeren in Swift
Zoeken…
Een lijst met namen uit een lijst met persoon (personen) extraheren
Gegeven een Person
struct
struct Person {
let name: String
let birthYear: Int?
}
en een matrix van Person(s)
let persons = [
Person(name: "Walter White", birthYear: 1959),
Person(name: "Jesse Pinkman", birthYear: 1984),
Person(name: "Skyler White", birthYear: 1970),
Person(name: "Saul Goodman", birthYear: nil)
]
kunnen we een reeks van op te halen String
met daarin de name
eigendom van elke persoon.
let names = persons.map { $0.name }
// ["Walter White", "Jesse Pinkman", "Skyler White", "Saul Goodman"]
doorkruisen
let numbers = [3, 1, 4, 1, 5]
// non-functional
for (index, element) in numbers.enumerate() {
print(index, element)
}
// functional
numbers.enumerate().map { (index, element) in
print((index, element))
}
projecteren
Een functie toepassen op een verzameling / stroom en een nieuwe verzameling / stroom maken wordt een projectie genoemd .
/// Projection
var newReleases = [
[
"id": 70111470,
"title": "Die Hard",
"boxart": "http://cdn-0.nflximg.com/images/2891/DieHard.jpg",
"uri": "http://api.netflix.com/catalog/titles/movies/70111470",
"rating": [4.0],
"bookmark": []
],
[
"id": 654356453,
"title": "Bad Boys",
"boxart": "http://cdn-0.nflximg.com/images/2891/BadBoys.jpg",
"uri": "http://api.netflix.com/catalog/titles/movies/70111470",
"rating": [5.0],
"bookmark": [[ "id": 432534, "time": 65876586 ]]
],
[
"id": 65432445,
"title": "The Chamber",
"boxart": "http://cdn-0.nflximg.com/images/2891/TheChamber.jpg",
"uri": "http://api.netflix.com/catalog/titles/movies/70111470",
"rating": [4.0],
"bookmark": []
],
[
"id": 675465,
"title": "Fracture",
"boxart": "http://cdn-0.nflximg.com/images/2891/Fracture.jpg",
"uri": "http://api.netflix.com/catalog/titles/movies/70111470",
"rating": [5.0],
"bookmark": [[ "id": 432534, "time": 65876586 ]]
]
]
var videoAndTitlePairs = [[String: AnyObject]]()
newReleases.map { e in
videoAndTitlePairs.append(["id": e["id"] as! Int, "title": e["title"] as! String])
}
print(videoAndTitlePairs)
filtering
Maak een stream door de elementen te selecteren uit een stream die aan een bepaalde voorwaarde voldoen. Dit wordt filteren genoemd
var newReleases = [
[
"id": 70111470,
"title": "Die Hard",
"boxart": "http://cdn-0.nflximg.com/images/2891/DieHard.jpg",
"uri": "http://api.netflix.com/catalog/titles/movies/70111470",
"rating": 4.0,
"bookmark": []
],
[
"id": 654356453,
"title": "Bad Boys",
"boxart": "http://cdn-0.nflximg.com/images/2891/BadBoys.jpg",
"uri": "http://api.netflix.com/catalog/titles/movies/70111470",
"rating": 5.0,
"bookmark": [[ "id": 432534, "time": 65876586 ]]
],
[
"id": 65432445,
"title": "The Chamber",
"boxart": "http://cdn-0.nflximg.com/images/2891/TheChamber.jpg",
"uri": "http://api.netflix.com/catalog/titles/movies/70111470",
"rating": 4.0,
"bookmark": []
],
[
"id": 675465,
"title": "Fracture",
"boxart": "http://cdn-0.nflximg.com/images/2891/Fracture.jpg",
"uri": "http://api.netflix.com/catalog/titles/movies/70111470",
"rating": 5.0,
"bookmark": [[ "id": 432534, "time": 65876586 ]]
]
]
var videos1 = [[String: AnyObject]]()
/**
* Filtering using map
*/
newReleases.map { e in
if e["rating"] as! Float == 5.0 {
videos1.append(["id": e["id"] as! Int, "title": e["title"] as! String])
}
}
print(videos1)
var videos2 = [[String: AnyObject]]()
/**
* Filtering using filter and chaining
*/
newReleases
.filter{ e in
e["rating"] as! Float == 5.0
}
.map { e in
videos2.append(["id": e["id"] as! Int, "title": e["title"] as! String])
}
print(videos2)
Filter met structuren gebruiken
Vaak wilt u mogelijk structuren en andere complexe gegevenstypen filteren. Het zoeken naar een reeks structuren voor items die een bepaalde waarde bevatten, is een veel voorkomende taak en kan gemakkelijk worden bereikt in Swift met functionele programmeerfuncties. Bovendien is de code uiterst beknopt.
struct Painter {
enum Type { case Impressionist, Expressionist, Surrealist, Abstract, Pop }
var firstName: String
var lastName: String
var type: Type
}
let painters = [
Painter(firstName: "Claude", lastName: "Monet", type: .Impressionist),
Painter(firstName: "Edgar", lastName: "Degas", type: .Impressionist),
Painter(firstName: "Egon", lastName: "Schiele", type: .Expressionist),
Painter(firstName: "George", lastName: "Grosz", type: .Expressionist),
Painter(firstName: "Mark", lastName: "Rothko", type: .Abstract),
Painter(firstName: "Jackson", lastName: "Pollock", type: .Abstract),
Painter(firstName: "Pablo", lastName: "Picasso", type: .Surrealist),
Painter(firstName: "Andy", lastName: "Warhol", type: .Pop)
]
// list the expressionists
dump(painters.filter({$0.type == .Expressionist}))
// count the expressionists
dump(painters.filter({$0.type == .Expressionist}).count)
// prints "2"
// combine filter and map for more complex operations, for example listing all
// non-impressionist and non-expressionists by surname
dump(painters.filter({$0.type != .Impressionist && $0.type != .Expressionist})
.map({$0.lastName}).joinWithSeparator(", "))
// prints "Rothko, Pollock, Picasso, Warhol"
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