web-services
C＃.netとXamarinアプリケーション開発を使用してWebサービスをプログラムで呼び出す

前書き

備考

単純なGETメソッドの呼び出し

/// <summary>
    /// Simple Get method
    /// </summary>
    /// <returns> Json formated data </returns>
    public string GetJsonData1()
    {
        IOperations _Obj = ClsOperations.GetOperations();
        string url = "http://1.2.3.4:1234/Services/rest/CallService/WebRequest/"; 
        string jsonResult = _Obj.GetJsonResult(url);
        return jsonResult;
    }

データPOST / POSTメソッドを使用したWebサービスの呼び出し

        /// <summary>
    /// Post Method with input parameter
    /// </summary>
    /// <returns> Json formated data </returns>
    public string GetJsonData2()
    {
        IOperations _Obj = ClsOperations.GetOperations();
        string url = "http://1.2.3.4:1234/Services/rest/CallService/WebRequest/";
        Dictionary<string, object> objDec = new Dictionary<string, object>();
        objDec.Add("@FirstParameter", "Value1");
        objDec.Add("@SecondParameter", "Value2");
        objDec.Add("@ThirdParameter", "Value3");
        string jsonResult = _Obj.GetJsonResult(url, objDec);
        return jsonResult;
    }

データPOST / POSTメソッドを使用してWebサービスを呼び出す（JSON形式のデータ）

/// <summary>
    /// Post Method with Input/ data to post in JSON format 
    /// </summary>
    /// <returns> Json formated data </returns>
    public string GetJsonData3()
    {
        IOperations _Obj = ClsOperations.GetOperations();
        string url = "http://1.2.3.4:1234/Services/rest/CallService/WebRequest/";
        string inputjson = "{\"@FirstParameter\": \"Value1\",\"@SecondParameter\": \"Value2\",\"@ThirdParameter\": \"Value3\"}";
        string jsonResult = _Obj.GetJsonResult(url, null,inputjson );
        return jsonResult;
    }

出力付きのWebサービス呼び出しIEnumeratorオブジェクトとして

/// <summary>
    /// Post Method with Input/ data to post in JSON format Or you can send dictionary as shown in previous methods
    /// </summary>
    /// <returns> Json formated data </returns>
    public void  GetJsonData4()
    {
        IOperations _Obj = ClsOperations.GetOperations();
        string url = "http://1.2.3.4:1234/Services/rest/CallService/WebRequest/";
        string inputjson = "{\"@FirstParameter\": \"Value1\",\"@SecondParameter\": \"Value2\",\"@ThirdParameter\": \"Value3\"}";
        string jsonResult = _Obj.GetJsonResult(url, null, inputjson);
        IEnumerator objIEnumerator = _Obj.GetJsonEnumerableResult(jsonResult);
        // you can perform further operations on it

    }

リスト形式またはデータテーブル形式のWebサービス出力

    /// <summary>
        /// Post Method with Input/ data to post in JSON format Or you can send dictionary as shown in previous methods
        /// </summary>
        /// <returns> Json formated data </returns>
        public DataTable  GetJsonData6()
        {
            IOperations _Obj = ClsOperations.GetOperations();
            string url = "http://1.2.3.4:1234/Services/rest/CallService/WebRequest/";
            string inputjson = "{\"@FirstParameter\": \"Value1\",\"@SecondParameter\": \"Value2\",\"@ThirdParameter\": \"Value3\"}";
            IEnumerator objIEnumerator = _Obj.GetJsonEnumerableResult(url, null, inputjson);
            // you can perform further operations on it

            // If you want to convert it in Datatable / List

            List<ClsMyPropertyClass> lst = new List<ClsMyPropertyClass>();
            while (objIEnumerator.MoveNext())
            {
                lst.Add(Newtonsoft.Json.JsonConvert.DeserializeObject<ClsLineEDoDetails>(objIEnumerator.Current.ToString()));
            } 
// Upto this you will get List , and you can perform operations on it

            // Now if youu want result in datatable, here i written function for List to datatable conversion
            
            return CommonServiceCall.ToDataTable(lst);

        }

GETまたはPOSTメソッドを強制的に作成する

/* By Default if you send only url then automatically it will recognize as GET Method and if service having parameters with, Then automatically will convert to POST Method. But I observed some of the services having only URL but are POST Type. For the purpose you can forcefully make the method as you want. As bellow:  */
        /// <summary>
        /// If you want make the service call GET OR POST forcefully then 
        /// </summary>
        /// <returns> Json formated data </returns>
        public void GetJsonData5()
        {
            IOperations _Obj = ClsOperations.GetOperations();
            string url = "http://1.2.3.4:1234/Services/rest/CallService/WebRequest/";
            string inputjson = "{\"@FirstParameter\": \"Value1\",\"@SecondParameter\": \"Value2\",\"@ThirdParameter\": \"Value3\"}";
string  _result =   _ Obj.GetJsonResult(url, null, inputjson, ServiceType.POST);;
                     }